The heat transfer from the wire can also be calculated by:
$\dot{Q}=\frac{T_{s}-T_{\infty}}{\frac{1}{2\pi kL}ln(\frac{r_{o}+t}{r_{o}})}$
$h=\frac{Nu_{D}k}{D}=\frac{2152.5 \times 0.597}{2}=643.3W/m^{2}K$
Assuming $k=50W/mK$ for the wire material,
The rate of heat transfer is:
$I=\sqrt{\frac{\dot{Q}}{R}}$
The heat transfer from the not insulated pipe is given by:
The heat transfer from the wire can also be calculated by:
$\dot{Q}=\frac{T_{s}-T_{\infty}}{\frac{1}{2\pi kL}ln(\frac{r_{o}+t}{r_{o}})}$ The heat transfer from the wire can also
$h=\frac{Nu_{D}k}{D}=\frac{2152.5 \times 0.597}{2}=643.3W/m^{2}K$ The heat transfer from the wire can also
Assuming $k=50W/mK$ for the wire material, The heat transfer from the wire can also
The rate of heat transfer is:
$I=\sqrt{\frac{\dot{Q}}{R}}$
The heat transfer from the not insulated pipe is given by: